Correct Calculation for RT3 Ratio?

General Discussion
#1

On my last blood test requested from the doctor I was quite sure Free T3 was on the Requisition slip, but when the results came I didn’t see Free T3.

I had read on another forum that it can also be calculated by dividing Total T3 by RT3 = Ratio (The ratio # should be under 10, otherwise you have high RT3)

Then today I was trying to get some questions answered on a yahoo thyroid/adrenal forum and I was informed by a moderator that I am Hypo, but don’t have high RT3.

I decided to call Quest Diagnostics lab to determine the correct method for obtaining ratio. Of course they won’t speak with anyone other than my doctor. So now I am basicly waiting. Can anyone here say with confidence that they know the correct way of calculating RT3 ratio? If so, was the method I used right?

T4 Free 1.1 (0.8-1.8) mg/dL
T3 Total 93 (76-181) ng/dL

T3 Total 93 (76-181) ng/dL ?
RT3 26 (11-32) pg/mL ?

RT3 Ratio: 3.57 If my calculations are correct? I read it should be above 10.

#2

There is a much simpler concept than this ratio. And it is that you want 1) RT3 to be in the lower half of the range and 2) FT3 and FT4 to be at the very top of the range.

You should be able to achieve 1) by simply keeping your cortisol high enough. If doing so does not automatically achieve 2) (it rarely does), then you need to supplement with slow release T3 and, subsequently, with T4. This is the general outline of a “metabolism boosting” treatment, but it’s up to you and your doctor to define the details of its implementation.

#3

m_81,

thanks, that makes more sense. This is more in the line with what I was thinking. I’m closer to the highest end of the RT3, which puts me at 71% of the range. If you look at the T3, I’m 16% of that range. If those numbers were revered I would be much better.

#4

use this to find the ratio. i was so confused on mine as well because on my RT3 they didn’t even put in the stupid measurement lol. this got me to find it:

faqhelp.webs.com/rt3ratiot3meds.htm

#5

This is correct i think. I’ve seen this used elsewhere. Thanks for bringing this up bryce.